9x^2-28x+4=0

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Solution for 9x^2-28x+4=0 equation:



9x^2-28x+4=0
a = 9; b = -28; c = +4;
Δ = b2-4ac
Δ = -282-4·9·4
Δ = 640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{640}=\sqrt{64*10}=\sqrt{64}*\sqrt{10}=8\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-8\sqrt{10}}{2*9}=\frac{28-8\sqrt{10}}{18} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+8\sqrt{10}}{2*9}=\frac{28+8\sqrt{10}}{18} $

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